In this graph, there are 3 forced diagonals (7-12, 6-14 and 5-17) which divide this graph in to 4 parts. For the right most part it is a blunt nose fox so it has 4 ways of triangulations; for the second one there is only one way because it is a fox; the third one is again, a blunt nose fox with 4 ways; as for the last part we have to do case analysis:
Overall, there are 4*1*4*(14+4+5)=368 distinct ways to triangulation this graph
In this graph, there are a pair of diagonals that are mutual exclusive: 1-6 and 0-2, if we do case analysis based on that:
Over all, there are 132*4+42=570 distinct ways of triangulations.
If we put witness points near 18, 2, 7 and 10, and in between 4 and 5, we got 5 areas that does not overlap on any vertex, . Also, we can find 5 guards A, B, C, D and E that cover P, thus
, and we can get
If we put witness points near 18, 2 and 7, and in between 4 and 5, we got 4 areas that does not overlap, so . Also, we can find 4 guards A, B, C and D that cover P, thus
, and we can get
If we put witness points near 3, 10, 17 and 23, and in between 13 and 14, we got 5 areas that does not overlap on any vertex, . Also, we can find 5 guards A, B, C, D and E that cover P, thus
, and we can get
If we put witness points near 3, 10, 17 and 23, and in between 13 and 14, we got 5 areas that does not overlap, . Also, we can find 5 guards A, B, C, D and E that cover P, thus
, and we can get